-3.444x+6.02x^2=0

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Solution for -3.444x+6.02x^2=0 equation: 



-3.444x+6.02x^2=0

a = 6.02; b = -3.444; c = 0;
Δ = b2-4ac
Δ = -3.4442-4·6.02·0
Δ = 11.861136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.444)-\sqrt{11.861136}}{2*6.02}=\frac{3.444-\sqrt{11.861136}}{12.04}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.444)+\sqrt{11.861136}}{2*6.02}=\frac{3.444+\sqrt{11.861136}}{12.04}
$

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